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question using the op482?
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overgeo
electronics forum beginner


Joined: 13 Jul 2006
Posts: 12

PostPosted: Wed Jul 19, 2006 3:59 pm    Post subject: question using the op482? Reply with quote

Hi, i have a square signal, with positive at 15V, and negative with
-15V, and i will like to convert this signal so that 15V will be 15V,
and the -15V will be 0V, to do this i use an op482 as comparator, the
configuration is this, +IN = -5V, -IN = Square wave, V+ = 15V, V- = 0V,
but in the output i get a signal with a high value of 1.3, and a low
value of 0.3, some suggestion to obtain the signal that i want?. Thanks
in advance.
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Peter Bennett
electronics forum Guru Wannabe


Joined: 15 May 2005
Posts: 210

PostPosted: Thu Jul 20, 2006 1:37 am    Post subject: Re: question using the op482? Reply with quote

On 19 Jul 2006 08:59:14 -0700, overgeo@gmail.com wrote:

Quote:
Hi, i have a square signal, with positive at 15V, and negative with
-15V, and i will like to convert this signal so that 15V will be 15V,
and the -15V will be 0V, to do this i use an op482 as comparator, the
configuration is this, +IN = -5V, -IN = Square wave, V+ = 15V, V- = 0V,
but in the output i get a signal with a high value of 1.3, and a low
value of 0.3, some suggestion to obtain the signal that i want?. Thanks
in advance.


It appears from a quick look at the datasheet that this part is
intended to operate from +/-15V supplies, and the inputs should not go
within 4 volts of the negative supply - in other words, you can't use
it the way you want.

In any case, few, if any, op-amps or comparators will tolerate the
inputs going outside the supply voltages, so you won't be able to put
+IN to -5 if the negative supply is 0V, regardless of the part you
choose.


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Peter Bennett, VE7CEI
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